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Q.
A river $10\, m$ deep is flowing at $5\, ms ^{-1}$. The shearing stress between horizontal layers of the river is ( $\eta=10^{-3} SI$ units)
Mechanical Properties of Fluids
Solution:
Shearing stress $=\frac{\mid \text { viscous force } \mid}{\text { area }} $
$=\frac{\eta A \frac{d v}{d x}}{A}=\eta \frac{d v}{d x}$
$=10^{-3} \times \frac{5}{10} N / m ^{2}=0.5 \times 10^{-3} N / m ^{2}$