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  4. A ring starts to roll down the inclined plane of height h without slipping. The velocity when it reaches the ground is

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Q. A ring starts to roll down the inclined plane of height $h$ without slipping. The velocity when it reaches the ground is

NTA AbhyasNTA Abhyas 2020System of Particles and Rotational Motion

Solution:

Solution
$mgh=\frac{1}{2}mv^{2}+\frac{1}{2}Iω^{2}$
$=\frac{1}{2}mv^{2}+\frac{1}{2}mr^{2}\frac{v^{2}}{r^{2}}$
$gh=v^{2}$
$v=\sqrt{gh}$