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Q. A ring of radius $R$ rolls without slipping on a rough horizontal surface with a constant velocity. The radius of curvature at the highest point of the path followed by any particle on the ring is
Question

NTA AbhyasNTA Abhyas 2022

Solution:

Radius of Curvature is given by
$=\frac{\left(\text{velocity}\right)^{2}}{\text{Normal Acceleration}}$
$=\frac{\left(2 v\right)^{2}}{v^{2}/R}=4R$
Solution