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  4. A ring of mass M is kept on a horizontal rough surface. A force F is applied tangentially at its rim as shown. The coefficient of friction between the ring and the surface is μ . Then <img class=img-fluid question-image alt=Question src=https://cdn.tardigrade.in/q/nta/p-ieqzfxcsjmlc.png />

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Q. A ring of mass $M$ is kept on a horizontal rough surface. A force $F$ is applied tangentially at its rim as shown. The coefficient of friction between the ring and the surface is $\mu $ . Then
Question

NTA AbhyasNTA Abhyas 2020System of Particles and Rotational Motion

Solution:

Solution
$F-f=Ma$
$FR+fR=I\alpha $
$\text{a} = \alpha \text{R}$
Putting $I=MR^{2}$ and solving we get $f=0$