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Q. A ring of charge with radius $0.5 \, m$ has $0.002\pi \, m$ gap. If the ring carries a charge of $+1 C,$ the electric field at the centre is



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NTA AbhyasNTA Abhyas 2020Electrostatic Potential and Capacitance

Solution:

Approaximate charge on the element opposite to the gap is
$\Delta q=\frac{Q}{2 \pi r}\left(0.002 \pi \right)$
$=\frac{1}{2 \pi \left(0.5\right)}\times \frac{2 \pi }{1000}=2\times \left(10\right)^{- 3 \, }C$
$E=\frac{9 \times 10^9 \times 2 \times 10^{-3}}{(0.5)^2}=7.2 \times 10^7 \mathrm{~N} \mathrm{C}^{-1}$

Solution