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Q. A resistor and an inductor are connected to an ac supply of $120\, V$ and $50\, Hz$. The current in the circuit is $3\, A$. If the power consumed in the circuit is $108 \, W$, then the resistance in the circuit is

Alternating Current

Solution:

In an ac circuit, a pure inductor does not consume any power. Therefore, power is consumed by the resistor only.
$\therefore P=I_{ v }^{2} R $
or $ 108=(3)^{2} R $ or $ R=12 \, \Omega$