Question

A resistance of $900 \Omega$ is connected in series with a galvanometer of resistance $100 \Omega$. A potential difference of 1 volt produces 100 division deflection in the galvanometer. Find the figure of merit of galvanometer?

• A. $10^{-6} A / div$
• B. $10^{-4} A / div$
• C. $10^{-7} A / div$
• D. $10^{-5} A / div$

Answer 1

Answer: (D)

$K =\frac{ I }{\theta}=\frac{ V }{ R \theta}$
$K=\frac{1}{(900+100) 100}=\frac{1}{10^{5}}$
$K =10^{-5} A /$ division