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Q. A research satellite of mass 200 kg circles the earth in an orbit of average radius 3R/2, where R is the radius of the earth. Assuming the gravitational pull on a mass of 1 kg on the earths surface to be 10 N, the pull on the satellite will be:

KEAMKEAM 2002

Solution:

Given, $ 10=\frac{G\times 6\times {{10}^{24}}\times I}{{{(6.4\times {{10}^{6}})}^{2}}} $ $ \Rightarrow $ $ G=6.82\times {{10}^{-11}}N{{m}^{2}}/k{{g}^{2}} $ Therefore, $ {{F}_{satellite}}=\frac{6.82\times {{10}^{-11}}\times 6\times {{10}^{24}}\times 200}{{{\left( \frac{3\times 6.4\times {{10}^{6}}}{2} \right)}^{2}}} $ $ =889N $