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Q. A refrigerator works between $4^{\circ}C$ and $30^{\circ}C$. It is required to remove $600\, calories$ of heat every second in order to keep the temperature of the refrigerated space constant. The power required is : $(Take\, 1 \,cal\, =\, 4.2 \,Joules)$

NEETNEET 2016Thermodynamics

Solution:

$\beta = \frac{Q_2}{W} = \frac{T_2}{T_1 - T_2}$ (Where $Q_2$ is heat removed)
$\Rightarrow \, \frac{600 \times 4.2}{W} = \frac{277}{303 - 277}$
$ \Rightarrow \, W = 236.5 $ joule
$ \Rightarrow \, Power = \frac{W}{t} = \frac{236.5 \,joule}{1 sec} = 236.5 \, watt.$