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Q. A rectangular loop with a sliding connector of length $l=1.0\, m$ is situated in a uniform magnetic field $B=2 T$ perpendicular to the plane of loop. Resistance of connector is $r=2\, \Omega$.
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Two resistances of $6\, \Omega$ and $3\, \Omega$ are connected as shown in the figure. Find the external force (in newton) required to keep the connector moving with a constant velocity $v=2\, m / s$.

Electromagnetic Induction

Solution:

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$R_{\text{eff }}=\frac{3 \times 6}{3+6}+2=4\, \Omega$
$\therefore I=\frac{\varepsilon}{R_{ cff }}=\frac{B l v}{R_{\text{eff }}}=\frac{2 \times 1 \times 2}{4}=1\, A$
$\therefore F=I l B=1 \times 1 \times 2=2\, N$