Question

A reaction rate is given by $k=1.5 \times 10^{15} \exp (-25000 / RT ) s ^{-1}$ it means that

• A. half-life period of the reaction will be smaller at high temperature
• B. log vs T will give a straight line
• C. half-life of the reaction will be smaller at lower temperature
• D. log vs 1 / T will give a straight line having a slope of -25000

Answer 1

Answer: (A)

It is a first-order reaction rate. At high temperature, rate constant will be larger. The larger the value of $k$, the smaller will be the half-life period of first-order reaction.
$t _{1 / 2}=\frac{0.693}{k}$