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Q. A reaction has both $ \Delta \,H $ and $ \Delta \,S $ negative. The rate of reaction

CMC MedicalCMC Medical 2007

Solution:

$ \Delta G=\Delta H-T\Delta S $ Negative $ \Delta H $ favours the process. Negative $ \Delta S $ opposes the process. If temperature is decreased, opposing factor decreases. Hence, rate of reaction increases.