Question

$A$ reaction attains equilibrium state under standard conditions, then what is incorrect for this?

• A. Equilibrium constant $K = 0$
• B. Equilibrium constant $K = 1$
• C. $\Delta G^° = 0$ and $\Delta H^° = T\Delta S^°$
• D. $\Delta G = 0$ and $\Delta H = T\Delta S$

Answer 1

Answer: (A)

$\Delta G^{\circ} = 0$ at equilibrium under standard state.
Also, at equilibrium, $\Delta G = 0$
$\therefore \Delta H^{\circ}-T\Delta S^{\circ} = 0$
Also, $\Delta G^{\circ} = 2.303RT \,log \,K$
$\therefore K= 1$