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Q.
A ray of light passing from glass to water is incident on the glass-water interface at $65^{\circ}$. If the critical angle for the pair of media is $63^{\circ}$,
COMEDKCOMEDK 2012Ray Optics and Optical Instruments
Solution:
Here, critical angle, $\theta, = 63^{\circ}$
Angle of incidence, $i = 65^{\circ}$
Since the light is incident at an angle $i > \theta_c,$ then angle of deviation is given by,
$ \delta = \pi - 2i$
$ \, \, \, \, = 180^{\circ} - 2 \times 65^{\circ} = 50^{\circ}$