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Q. A ray of light is incident on $x$-axis at $A \equiv(-2,0)$ and after reflection from $x$-axis it intersect the curve $y^{2}=4 x$ in $\mathrm{P}$ and $\mathrm{Q}$. If $\frac{1}{\mathrm{AP}}+\frac{1}{\mathrm{AQ}}=\frac{1}{4}$ ( $\mathrm{P}, \mathrm{Q}$ being in $\mathrm{I}$-quadrant), then equation of incident ray, is

Straight Lines

Solution:

Correct answer is (c) $y+x \sqrt{3}+2 \sqrt{3}=0$