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Q. A ray of light is incident on a plane mirror at an angle of $60^\circ$. The angle of deviation produced by the mirror is

AFMCAFMC 2009Ray Optics and Optical Instruments

Solution:

Here, angle of incidence, $i=60^{\circ}$
image
$\therefore $ Angle of deviation
$\delta =180^{\circ}-(i+r) $
$=180^{\circ}-2 i \,\,\,\,\,\,\, (\text { As } i=r) $
$ =180^{\circ}-2 \times 60^{\circ}=60^{\circ}$