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  4. A ray of light is incident on a 60° prism at the minimum deviation position. The angle of refraction at the first face (i.e; incident face) of the prism is

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Q. A ray of light is incident on a $60^{\circ}$ prism at the minimum deviation position. The angle of refraction at the first face (i.e; incident face) of the prism is

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Solution:

Angle of prism, $A =r_{1}+r_{2}$
For minimum deviation
$r_{1}=r_{2}=r $
$\therefore A=2 r$
Given, $A=60^{\circ}$
Hence, $r=\frac{A}{2}=\frac{60^{\circ}}{2}=30^{\circ}$

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