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Q. A ray of light is incident at $50^{\circ}$ on the middle of one of the two mirrors arranged at an angle of $60^{\circ}$ between them. The ray then touches the second mirror, gets reflected back to the first mirror, making an angle of incidence $\ldots \ldots$

WBJEEWBJEE 2007

Solution:

Let required angle be $ \theta . $
image In $\Delta A B C$,
$90^{\circ}-\theta+140^{\circ}+20^{\circ}$
$=180^{\circ}$
$\Rightarrow \theta=70^{\circ}$