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Q. A ray of light falls on a transparent sphere with centre $C$ as shown in the figure. The ray emerges from sphere parallel to line $A B .$ The refractive index of sphere is
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Ray Optics and Optical Instruments

Solution:

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Apply Snell's law at points $A$ and $B$
$1 \sin 60^{\circ}=\mu \sin r \,\,\,\,\, \ldots( i )$
$\mu \sin r=1 \sin \phi\,\,\,\,\dots(ii)$
Solving equations (i) and (ii), we get $\phi=60^{\circ}$
Also, $2 r+180^{\circ}-\phi=180^{\circ}$
$2 r+180^{\circ}-60^{\circ}=180^{\circ}$
or $2 r=60^{\circ}$ or $r=30^{\circ}$
From equation (i), we get $\mu=\frac{\sin 60^{\circ}}{\sin ^{\circ}}=\frac{\sin 60^{\circ}}{\sin{cin} 30^{\circ}}=\sqrt{3}$