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Q. A ray of light along $x+\sqrt{3 y}=\sqrt{3}$ gets reflected upon reaching $x$-axis, the equation of the reflected ray is

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Solution:

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Hint : $A \equiv(\sqrt{3}, 0)$
Let, $B(0,1)$
$\therefore B \equiv(0,-1)$
$\therefore $ Equation of $A B': \frac{y-0}{0+1}=\frac{x-\sqrt{3}}{\sqrt{3}-0} $
$\Rightarrow \sqrt{3} y=x-\sqrt{3}$