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Physics
A rain drop of radius 0.3 mm has a terminal velocity in air is 1 m/s. The viscosity of air is 8 × 10-5 poise. The viscous force on it is
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Q. A rain drop of radius $0.3\, mm$ has a terminal velocity in air is $1\, m/s$. The viscosity of air is $8 \times 10^{-5}$ poise. The viscous force on it is
VITEEE
VITEEE 2019
A
$45.2 \times 10^{-4}$ dyne
B
$101.73 \times 10^{-5}$ dyne
C
$16.95 \times 10^{-4}$ dyne
D
$16.95 \times 10^{-5}$ dyne
Solution:
Radius of drop, $r = 0.3\, mm = 0.03\, cm$
Terminal velocity, $v = 1 \,m/s = 100\, cm/sec$
Viscosity of air, $\eta=8\times10^{-5}$ poise
Viscous force, $f = 6\,\pi\eta rv$
$F=6\times3.14\times\left(8\times10^{-5}\right)\times0.03\times100=4.42\times10^{-3}$ dyne