1. Tardigrade
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  3. Physics
  4. A railway track runs parallel to a road until a turn brings the road to railway crossing. A cyclist rides along the road every day at a constant speed 20 km/hr. He normally meets a train that travels in same direction at the crossing. One day he was late by 25 minutes and met the train 10 km before the railway crossing. Find the speed of the train.

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Q. A railway track runs parallel to a road until a turn brings the road to railway crossing. A cyclist rides along the road every day at a constant speed $20 \,km/hr$. He normally meets a train that travels in same direction at the crossing. One day he was late by $25$ minutes and met the train $10 \,km$ before the railway crossing. Find the speed of the train.

Motion in a Straight Line

Solution:

$t_{\text{cycle}} = \frac{10\,km}{20 \,kmh^{-1}}$
$ = \frac{1}{2} h = 30 \,\min$
$\Delta t = 5\,\min = \frac{5}{60} hr$
image
Train running as per schedule.
So $V_{\text{train}} = \frac{10}{(5/60)} $
$ = \frac{10 \times 60}{5}$
$ = 120\, kmh^{-1}$