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Q. A raft of wood of mass $120\, kg$ floats in water. The weight that can be put on the raft to make it just sink, should be $\left(d_{ \text{raft} }=600\, kg / m ^{3}\right)$

JIPMERJIPMER 2005

Solution:

Volume of raft is given by
$V=\frac{m}{d}=\frac{120}{600}=0.2\, m ^{3}$
If the raft is immersed fully in water.
Then weight of water displaced is $=V d_{\text {water }}$
$=0.2 \times 10^{3}=200 \,kg$
Hence, the additional weight which is supported by raft
$=200\, kg -120\, kg =80\, kg$