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Physics
A radioactive sample of half-life 10 days, contains 1000x nuclei. Number of original nuclei present after 5 days is
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Q. A radioactive sample of half-life $10$ days, contains $1000x$ nuclei. Number of original nuclei present after $5$ days is
NTA Abhyas
NTA Abhyas 2020
Nuclei
A
$707x$
73%
B
$750x \, $
5%
C
$500x \, $
18%
D
$250x \, $
5%
Solution:
The number of radioactive nuclei left after n half lives is
$N=\frac{N_{0}}{2^{n}}$
$for 5 days n=\frac{1}{2}$
So, $N=\frac{1000 x}{2^{\frac{1}{2}}}=\frac{1000 x}{\sqrt{2}}$
$=\frac{1000 x}{1.414}=\left(0.707\right)1000x$
$=707x$