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Q. A radioactive nucleus undergoes a series of decay according to the scheme: $A \stackrel{\alpha}{\longrightarrow } A _{1} \stackrel{\beta}{\longrightarrow } A _{2} \stackrel{\alpha}{\longrightarrow } A _{3} \stackrel{\gamma}{\longrightarrow } A _{4}$ If the mass number and atomic number of $A$ are 180 and 72 respectively, then what are these number for $A _{4}$

Nuclei

Solution:

$180-4-0-4-0=172$ Mass number
$72-2+1-2+0=69$ Atomic number