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  4. A radioactive element X emits six α-particles and four β-particles leading to end product 82208 P b . X is

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Q. A radioactive element $X$ emits six $\alpha$-particles and four $\beta$-particles leading to end product ${ }_{82}^{208} P b . X$ is

Nuclei

Solution:

Calculating $Z_{x}=82+6 \times 2-4$
$=90$
$A_{x}=208+6 \times 4=232$