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Q.
A radioactive decay can form an isotope of the original nucleus with the emission of particles
Nuclei
Solution:
Emission of $\alpha$ particle decreases the atomic number and the mass number by $2$ and $4$ respectively. Emission of $\beta$ -particle increases the atomic number by $1$ while the mass number remains unchanged. Therefore, after the emission of one $\alpha$ and two $\beta$ -particles, the atomic number remains the same while the mass number decreases by $4$ . Hence, the emitted nucleus is the isotope of the original nucleus.