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Q. A radio transmitter radiates $1 \,kW$ power at a wavelength $198.6\, m$. How many photons does it emit per second?

Bihar CECEBihar CECE 2014Dual Nature of Radiation and Matter

Solution:

$ n=\frac{P}{E}=\frac{P}{hv}=\frac{P\lambda }{hc} $
$ =\frac{1000\times 198.6}{6.6\times {{10}^{-34}}\times 3\times {{10}^{8}}}\approx {{10}^{30}} $