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Q. A radio-active elements has half-life of $15$ years. What is the fraction that will decay in $30$ years?

KCETKCET 2020

Solution:

Fraction un decayed is given as,
$N / N _{0}=(1 / 2)^{( t / T )}$
Here, $t =30$ years and $T =15$ years
So,
$N / N _{0}=(1 / 2)^{((30 \text { years }) /(15 \text { years }))}$
or, $N / N _{0}=(1 / 2)^{2}$
or, $N / N _{0}=1 / 4$
Therefore,
Fraction un decayed $=1- N / N _{0}$
or, Fraction un decayed $=1-(1 / 4)$
or, Fraction un decayed $=3 / 4=0.75$