Question

A purse contains $4$ copper coins and $3$ silver coins, the second purse contains $6$ copper coins and $2$ silver coins. If a coin is drawn out of any purse, then the probability that it is a copper coin is

• A. $\frac{4}{7}$
• B. $\frac{3}{4}$
• C. $\frac{37}{56}$
• D. None of these

Answer 1

Answer: (C)

$\therefore $ Required probability $=\frac{1}{2} \cdot \frac{4}{7}+\frac{1}{2} \cdot \frac{6}{8}=\frac{37}{56}$