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  4. A pure breeding pea plant with round yellow seeds was crossed with pea plant having wrinkled green seeds. On selfing of F1 hybrid of his cross 64 progenies were obtained in F2 generation. Find out the number of F2 progenies showing non-parental characters.

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Q. A pure breeding pea plant with round yellow seeds was crossed with pea plant having wrinkled green seeds. On selfing of $F_1$ hybrid of his cross $64$ progenies were obtained in $F_2$ generation. Find out the number of $F_2$ progenies showing non-parental characters.

KCETKCET 2020

Solution:

The $F _{2}$ phenotypic ratio in a dihybrid cross is $9 : 3 : 3 : 1$. The first and last term in ratio i.e, 9 and $1$ represent the parental genotypes while the second and third term i.e, $3$ and $3$ represent the recombinant genotypes. Therefore, the number of $F _{2}$ progenies out of $64$ progenies showing non-parental characters will be = $(6 / 16) \times 64=24 .$