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Q. A pulley system is attached to a massless board as shown below. The board pivots only at the pivot point. A $10\, kg$ mass $M$ sits exactly in the middle of the board.
image
If the angle $\theta$ is $60^{\circ}$, what is the force $F$ (in newton) necessary to hold the board in the position shown.

System of Particles and Rotational Motion

Solution:

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for equilibrium $\left|M g \frac{l}{2}\right|=|2 F| l$
$F=\frac{m g}{4}=\frac{100}{4}=25 \,N .$