1. Tardigrade
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  3. Physics
  4. A proton moving with a velocity 3 × 105 m / s enters in a magnetic field of 0.3 tesla at an angle of 30° with the field, the radius of helix of its path will be: (e/m for proton .=108 C / kg )

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Q. A proton moving with a velocity $3 \times 10^{5} m / s$ enters in a magnetic field of $0.3$ tesla at an angle of $30^{\circ}$ with the field, the radius of helix of its path will be : (e/m for proton $\left.=10^{8} C / kg \right)$

Solution:

Correct answer is (b) 0.5 cm