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Physics
A proton is about 1840 times heavier than an electron. When it is accelerated by a potential difference of 1 kV, its kinetic energy will be
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Q. A proton is about $1840$ times heavier than an electron. When it is accelerated by a potential difference of $1\, kV$, its kinetic energy will be
Electrostatic Potential and Capacitance
A
1840 keV
14%
B
1 / 1840 keV
14%
C
1 keV
62%
D
920 keV
10%
Solution:
Kinetic energy of proton,
$K=e \Delta V=e \times 10^{3} V =1\, keV$