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Physics
A proper combination of 3 NOT and 1 NAND gates is shown. If A=0, B=1, C=1, then the output of this combination is
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Q. A proper combination of $3\, NOT$ and $1\, NAND$ gates is shown. If $A=0,\, B=1,\, C=1$, then the output of this combination is
AIIMS
AIIMS 2017
A
1
B
0
C
not predictable
D
None of these
Solution:
The simplified circuit is shown in figure below.
So, output $y=\overline{\bar{A} \cdot \bar{B} \cdot \bar{C}}$
If $A=0, B=1, C=1$
$\therefore y=\overline{\bar{0} \cdot \bar{1} \cdot \bar{1}}=\overline{1 \cdot 0 \cdot 0}=\bar{0}=1$