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  4. A projectile is projected with speed 49 ms-1 at an angle of 30° with horizontal. The time taken by the projectile to reach the highest point is

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Q. A projectile is projected with speed $49\,ms^{-1}$ at an angle of $30^{\circ}$ with horizontal. The time taken by the projectile to reach the highest point is

UP CPMTUP CPMT 2010Motion in a Plane

Solution:

Here,
Velocity of projection, $u=49\, m \, s^{-1}$
Angle of projection, $\theta=30^{\circ}$
Time taken by the projectile to reach the highest point is
$t=\frac{u\,sin\,\theta}{g}$
$=\frac{\left(49\,m\,s^{-1}\right)\left(sin\,30^{\circ}\right)}{9.8 \, m \,s^{-2}}$
$=2.5 \, s$