Thank you for reporting, we will resolve it shortly
Q.
A projectile is moving at $20 m / s$ at its highest point, where it breaks into equal parts due to an internal explosion. One part moves vertically up at $30 m / s$ with respect to he ground. Then the other part will move at:
Using momentum conservation,
$
\begin{array}{l}
m \times 20 \hat{ i }= m / 2 \times 30 \hat{ j }+ m / 2 \times x \\
x =40 \hat{ i }-30 \hat{ j } \\
\Rightarrow | x |=50
\end{array}
$