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Q. A projectile $A$ is thrown at an angle of $30^{\circ}$ to the horizontal from point $P$. At the same time, another projectile $B$ is thrown with velocity $v _{2}$ upwards from the point $Q$ vertically below the highest point. For $B$ to collide with $A , \frac{ v _{2}}{ v _{1}}$ should bePhysics Question Image

BITSATBITSAT 2020

Solution:

This happen when vertical velocity of both are same.
$\therefore v_{2}=v_{1} \sin 30^{\circ} $
or $ \frac{v_{2}}{v_{1}}=\frac{1}{2}$