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Q. A prism of refractive index $n_{1}$ and another prism of refractive index $n_{2}$ are stuck together (as shown in the figure). $n_{1}$ and $n_{2}$ depend on $\lambda$, the wavelength of light, according to the relation $n_{1}=1.2+\frac{10.8 \times 10^{-14}}{\lambda^{2}}$ and $n_{2}=1.45+\frac{1.8 \times 10^{-14}}{\lambda^{2}}$ The wavelength for which rays incident at any angle on the interface $B C$ pass through without bending at that interface will be______ $nm$.Physics Question Image

JEE MainJEE Main 2021Ray Optics and Optical Instruments

Solution:

For no bending, $n_{1}=n_{2}$
$1.2+\frac{10.8 \times 10^{-14}}{\lambda^{2}}=1.45+\frac{1.8 \times 10^{-4}}{\lambda^{2}}$
On solving,
$9 \times 10^{-14}=25 \lambda^{2}$
$\lambda=6 \times 10^{-7}$
$\lambda=600\, nm$