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Q. A prism has a refracting angle of $60^{\circ}$. When placed in the position of minimum deviation, it produces a deviation of $30^{\circ}$. The angle of incidence is

VITEEEVITEEE 2017

Solution:

$\mu=\frac{\sin i}{\sin r}=\frac{\sin \left(\frac{\delta +A}{2}\right)}{\sin (A / 2)}$
$r=A / 2$
$\frac{\sin (i)}{\sin (A / 2)}=\frac{\sin \left(\frac{\delta +A}{2}\right)}{\sin (A / 2)}$
$i=(\delta+A) / 2$
$=\frac{30+60}{2}$
$=45^{\circ}$