Q. A printed page is pressed by a glass of water. The refractive index of the glass and water is $1.5$ and $1.33$ , respectively. If the thickness of the bottom of glass is $1 \,cm$ and depth of water is $5 \,cm$ , how much the page will appear to be shifted if viewed from the top ?
Solution:
Real depth = $5 \,cm + 1\,cm = 6\, cm$
Apparent depth-$\frac{d_{1}}{\mu_{1}} +\frac{d_{2}}{\mu_{2}}$ $+\ldots$
$=\frac{5}{1.33}+\frac{1}{1.5}$
$\simeq 3.8+0.7 \simeq 4.5\, cm$
$\therefore $ Shift $=6 cm -4.5 cm \cong 1.5 cm$
