Question Error Report

Thank you for reporting, we will resolve it shortly

Back to Question

Q. A primary alcohol, $C_{3} H_{8} O(A)$ on heating with sulphuric acid undergo dehydration to give an alkene, $B . B$ when reacted with $H C l$ gave $C$, which on treatment with aqueous $KOH$ gives compound $D\left( C _{3} H _{8} O \right)$. $A$ and $D$ are

Alcohols Phenols and Ethers

Solution:

$\underset{(A)}{CH _{3} CH _{2} CH _{2} OH }\xrightarrow[H_2SO_4]{\Delta}\underset{(B)}{CH _{3} CH = CH _{2}+ H _{2} O}$