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Q. A power transformer is used to step up an alternating e.m.f. of $220\, V$ to $11\, kV$ to transmit $4.4\, kW$ of power. If the primary coil has $1000$ turns, what is the current rating of the secondary? (Assume $100 \%$ efficiency for the transformer)

Electromagnetic Induction

Solution:

$i_{s}=\frac{P_{s}}{V_{s}}=\frac{4.4 \times 10^{3}}{11 \times 10^{3}}=0.4\, A$