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Q. A potentiometer wire of $10m$ length and having a resistance of $1ohmm^{- 1}$ is connected to an accumulator of emf $2.2volt$ and a high resistance box. To obtain a potential gradient of $2.2$ mili volt/ meter, the value of resistance used from the resistance box will be :

NTA AbhyasNTA Abhyas 2020

Solution:

Solution
$R_{P m}=10\Omega$
Potential gradient $=\frac{V_{P M}}{L}=\frac{I R_{P M}}{L}=\frac{E R_{P M}}{\left(R + R_{P m}\right) L}$