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Physics
A potential difference of 10 V is applied across a conductor of 1000 Ω. The number of electrons flowing through the conductor in 300 s is
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Q. A potential difference of $10 \,V$ is applied across a conductor of $1000 \,\Omega$. The number of electrons flowing through the conductor in $300 \,s$ is
Current Electricity
A
$1.875 \times 10^{16}$
8%
B
$1.875 \times 10^{17}$
16%
C
$1.875 \times 10^{22}$
11%
D
$1.875 \times 10^{19}$
65%
Solution:
$i=\frac{10}{1000}=0.01 \,A$
$n=\frac{0.01}{1.6 \times 10^{-19}}$