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  4. A positively charged ball hangs from a silk thread. If we put a positive test charge q0 at a point and measure F / q0, then it can be predicted that the electric field strength E is

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Q. A positively charged ball hangs from a silk thread. If we put a positive test charge $q_{0}$ at a point and measure $F / q_{0}$, then it can be predicted that the electric field strength $E$ is

Electric Charges and Fields

Solution:

Because of the presence of positive test charge $q_{0}$ in front of positively charged ball, charge on the ball will be redistributed, less charge on the front half surface and more charge on the back half surface. As a result of this net force $F$ between ball and point charge will decrease i.e., actual electric field will be greater than $F / q_{0}$