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  4. A positively charged ball hangs from a long silk thread. Electric field at a certain point (at the same horizontal level of ball) due to the ball is E . If now put a positive test charge q0 at this point and measure (F/q0) , here F is the force on q0 due to the charged ball. Then E is:

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Q. A positively charged ball hangs from a long silk thread. Electric field at a certain point (at the same horizontal level of ball) due to the ball is $E$ . If now put a positive test charge $q_{0}$ at this point and measure $\frac{F}{q_{0}}$ , here $F$ is the force on $q_{0}$ due to the charged ball. Then $E$ is:

NTA AbhyasNTA Abhyas 2022

Solution:

$E=\frac{k Q}{r^{2}}$ .....(i)

Solution
$F=\frac{k Q q_{0}}{r_{1}^{2}} \, \, \Rightarrow \, \, \frac{F}{q_{0}}=\frac{k Q}{r_{1}^{2}}$ ....(ii)
As $r_{1}>r,$ so from equation (i) and (ii), we get $E>\frac{F}{q_{0}}$