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Physics
A polyatomic gas with n degrees of freedom has a mean energy per molecule given:-
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Q. A polyatomic gas with $n$ degrees of freedom has a mean energy per molecule given:-
NTA Abhyas
NTA Abhyas 2020
A
$\frac{n k T}{N}$
B
$\frac{n k T}{2 N}$
C
$\frac{n k T}{2}$
D
$\frac{3 k T}{2}$
Solution:
$K.E.$ per degree of freedom $=\frac{1}{2}kT$ For polyatomic gas, mean $K.E.=\frac{n k T}{2}$