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Q. A point traversed half of the distance with a velocity $v_0$. The half of remaining part of the distance was covered with velocity $v_1$ & second half of remaining part by $v_2$ velocity. The mean velocity of the point, averaged over the whole time of motion is

Motion in a Straight Line

Solution:

Let the total distance be $d$.
Then for first half distance, time $=\frac{d}{2 v_0}$, next distance.
$=v_1 t$ and last half distance $=v_2 t$
$\therefore v _1 t + v _2 t =\frac{ d }{2} ; t =\frac{ d }{2\left( v _1+ v _2\right)}$
Now average speed
$t=\frac{d}{\frac{d}{2 v_0}+\frac{d}{2\left(v_1+v_2\right)}+\frac{d}{2\left(v_1+v_2\right)}}$
$=\frac{2 v_0\left(v_1+v_2\right)}{\left(v_1+v_2\right)+2 v_0}$