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Q. A point on the straight line $3x+5y=15$ , which is equidistant from the coordinate axes will lie only in

NTA AbhyasNTA Abhyas 2022

Solution:

Solution
Now, $\left|\frac{15 - 3 t}{5}\right|=\left|\right.t\left|\right.$
$\Rightarrow \frac{15 - 3 t}{5}=t$ or $\frac{15 - 3 t}{5}=-t$
$\therefore t=\frac{15}{8}$ or $t=\frac{- 15}{2}$
So, $P\left(\frac{15}{8} , \frac{15}{8}\right)\in I^{\text{st }}$ quadrant
or $P\left(\frac{- 15}{2} , \frac{15}{2}\right)\in \left(II\right)^{nd}$ quadrant